An octahedral complex of M^{+3} with NH_3 and | vedclass

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(D) The complex has the formula $[M(NH_3)_4(NO_2)_2]^+$. Since there are two $NO_2^-$ ligands,they can be arranged in $cis$ or $trans$ positions,which

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Both $(a)$ and $(b)$

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(D) The complex has the formula $[M(NH_3)_4(NO_2)_2]^+$. Since there are two $NO_2^-$ ligands,they can be arranged in $cis$ or $trans$ positions,which leads to geometrical isomerism. Additionally,the $NO_2^-$ ligand is an ambidentate ligand,meaning it can coordinate through either the $N$ atom or the $O$ atom. Since the complex contains both $M-N$ and $M-O$ linkages,it exhibits linkage isomerism. Therefore,the complex shows both geometrical and linkage isomerism.

List-$I$ (Complexes)	List-$II$ (Types)
$a$. $[Co(NH_3)_5NO_2]Cl_2$ and $[Co(NH_3)_5ONO]Cl_2$	$i$. Linkage isomerism
$b$. $[Cr(NH_3)_6][Co(CN)_6]$ and $[Cr(CN)_6][Co(NH_3)_6]$	$ii$. Coordination isomerism
$c$. $[Co(NH_3)_5(SO_4)]Br$ and $[Co(NH_3)_5Br]SO_4$	$iii$. Ionisation isomerism
$d$. $[Cr(H_2O)_6]Cl_3$ and $[Cr(H_2O)_5Cl]Cl_2 \cdot H_2O$	$iv$. Solvate isomerism

An octahedral complex of $M^{+3}$ with $NH_3$ and $NO_2^{-}$ ligands has four $M-N$ linkages and two $M-O$ linkages. Which type of isomerism will such a complex exhibit?

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